Three identical bulbs are connected in parallel with battery the current drawn from the battery is 6A . If one of the body gets future what will be the total current drawn from the battery?
Three identical bulbs are connected in parallel with battery the current drawn from the battery is 6 A . If one of the bulb gets fuse what will be the total current drawn from the battery?
Answer:
The current (I) drawn is 4 A
Given:
Current in circuit a (I₁) = 6 A.
Let Current in circuit b be I₂
Explanation:
Now lets consider figure 'a'
As the three bulbs each of resistance R are connected in parallel, then their equivalent resistance will be,
Substituting the values,
Hence, equivalent resistance is R/3 Ω.
Substituting the values,
∴ We got the potential as 2 volts.
Now, this potential is same in circuit 'b'. and we need not consider fused resistor R.
Now, lets find equivalent resistance of rest two bulbs.
Substituting the values,
Hence, in circuit b equivalent resistance is R/2 Ω.
Answers & Comments
Verified answer
Correct Question:
Three identical bulbs are connected in parallel with battery the current drawn from the battery is 6 A . If one of the bulb gets fuse what will be the total current drawn from the battery?
Answer:
Given:
Explanation:
Now lets consider figure 'a'
As the three bulbs each of resistance R are connected in parallel, then their equivalent resistance will be,
Substituting the values,
Hence, equivalent resistance is R/3 Ω.
Substituting the values,
∴ We got the potential as 2 volts.
Now, this potential is same in circuit 'b'. and we need not consider fused resistor R.
Now, lets find equivalent resistance of rest two bulbs.
Substituting the values,
Hence, in circuit b equivalent resistance is R/2 Ω.
Substituting the values,
∴ The current (I) drawn from battery is 4 A.