Three friends Amit Mayank and Rekha playing with Ball by standing on a circle at points A B and C respectively on the boundary of the circle. Rekha throws a ball to Amit, Amit to Mayank and Mayank to Rekha the all are equal distance and each other and radius of the circle is 20 m.
answer the following question:-
find the distance between Amit and Mayank
Answers & Comments
Question:-
➦ Three friends Amit Mayank and Rekha playing with Ball by standing on a circle at points A B and C respectively on the boundary of the circle. Rekha throws a ball to Amit, Amit to Mayank and Mayank to Rekha the all are equal distance and each other and radius of the circle is 20 m.
answer the following question:-
find the distance between Amit and Mayank.
Correct answer:-
➦ Given:
AB = BC = CA
To Find:
(i) ∠BOC
(ii) OBC + ∠OCB
Explanation:-
In the given figure,
AB = BC = CA (Given)
In A ABC is equilateral.
So, ∠A = ∠B = ∠C = 60°
OA = OB = OC (Radius)
Therefore, ∠BCO = OCB = 30° (Equal sides have equal opposite angles)
Using angle sum property in AOBC
BCO + BCO + OCB + COB = 180°
BCO + OCB = 60°
COB = 120°
Answer = 120°,60°.
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