Question:-

➦ Three friends Amit Mayank and Rekha playing with Ball by standing on a circle at points A B and C respectively on the boundary of the circle. Rekha throws a ball to Amit, Amit to Mayank and Mayank to Rekha the all are equal distance and each other and radius of the circle is 20 m. answer the following question:- Find the distance between Amit and Mayank.

Correct answer:-

➦ 1st: 120 Degree

2nd: 60 Degree

Step-by-step explanation:-

➦ ABC is an Equilateral Triangle.

ANGLE O = 2*

ANGLE A (THE ANGLE SUBTENDED BY AN ARC DOUBLE THE ANGLE SUBTENDED BY IT AT ANY POINT ON THE REMAINING PART OF THE CIRCLE).

So,

Angle O = 2* Angle A

O= 2*60

O = 120 degree

2nd

OBC = OCB

ANGLE OBC + OBC + COB = 180

ANGLE OBC + OCB = 180 - 120

Angle OBC + Angle OCB = 60

ANGLE 2*OBC = 60

ANGLE OBC = 30

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Answer:

Amit to Mayank distance

Three friends Amit Mayank and Rekha playing with Ball by standing on a circle at points A B and C respectively on the boundary of the circle. Rekha throws a ball to Amit, Amit to Mayank and Mayank to Rekha the all are equal distance and each other and radius of the circle is 20 m. answer the following question:- Find the distance between Amit and Mayank

The distance between Amit and Mayank on the boundary of the circle can be calculated using the circumference formula. Since they are standing at equidistant points on the circle, the distance would be one-third of the circle's circumference.

The formula for the circumference (C) of a circle is C = 2πr, where r is the radius. In this case, the radius is given as 20 meters.

�

=

2

�

×

20

C=2π×20

Now, find one-third of the circumference:

Distance between Amit and Mayank

=

1

3

×

�

Distance between Amit and Mayank=

3

1

×C