Three combination circuits, A, B and C, containing three identical resistors are illustrated below. Arrange the circuits in decreasing order of total resistance. (With Solutions and Explanations)
Here's How: In A. one resistor is in series and other two are in parallel which means A has the highest current .
In B. one resistor is in parallel with two resistors in series which gives a lesser current than that is of circuit A.
In C. All three are in parallel which gives the lowest current in all the circuit.
If you think that's incorrect you can also imagine resistors having 2,3,4 ohm which gives the highest current in circuit A, then in Circuit B and the lowest in Circuit C.
The correct order of total resistance in decreasing order is: B. C, A, B
To compare the total resistance of the three combination circuits A, B, and C, analyze each circuit and calculate their total resistances. Let's go through each circuit step by step:
Combination 1:
This circuit has two parallel resistors (let's call them R1 and R2) connected in parallel with a single resistor (let's call it R3).
The total resistance of two resistors in parallel can be calculated using the formula: 1/R_total = 1/R1 + 1/R2
Let's assume all resistors are identical, so R1 = R2 = R, and the total resistance of the two parallel resistors is: 1/R_total_parallel = 1/R + 1/R = 2/R => R_total_parallel = R/2
Now, the total resistance of the entire combination 1 (R_total_combination_1) is the sum of the total resistance of the parallel resistors and the single resistor: R_total_combination_1 = R_total_parallel + R3 = R/2 + R = 3R/2
Combination 2:
This circuit is a combination of a series and a parallel combination.
Let's assume all resistors are identical, so the total resistance of the parallel resistors (let's call it R_total_parallel_combination2) is: R_total_parallel_combination2 = R/2
The total resistance of two resistors in series can be calculated by simply adding them: R_total_series = R + R = 2R
Now, the total resistance of the entire combination 2 (R_total_combination_2) is the sum of the total resistance of the parallel resistors and the total resistance of the series resistors: R_total_combination_2 = R_total_parallel_combination2 + R_total_series = R/2 + 2R = 5R/2
Combination 3:
This circuit has three resistors connected in parallel.
Let's assume all resistors are identical, so the total resistance of three parallel resistors (R_total_combination_3) is: R_total_combination_3 = R/3
Now, let's arrange the total resistances of the three combinations in decreasing order:
Combination 2: R_total_combination_2 = 5R/2
Combination 1: R_total_combination_1 = 3R/2
Combination 3: R_total_combination_3 = R/3
So, the correct order of total resistance in decreasing order is: B. C, A, B.
Answers & Comments
Answer:
Answer would be option D
Explanation:
Here's How: In A. one resistor is in series and other two are in parallel which means A has the highest current .
In B. one resistor is in parallel with two resistors in series which gives a lesser current than that is of circuit A.
In C. All three are in parallel which gives the lowest current in all the circuit.
If you think that's incorrect you can also imagine resistors having 2,3,4 ohm which gives the highest current in circuit A, then in Circuit B and the lowest in Circuit C.
The correct order of total resistance in decreasing order is: B. C, A, B
To compare the total resistance of the three combination circuits A, B, and C, analyze each circuit and calculate their total resistances. Let's go through each circuit step by step:
Combination 1:
Combination 2:
Combination 3:
Now, let's arrange the total resistances of the three combinations in decreasing order:
So, the correct order of total resistance in decreasing order is: B. C, A, B.
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