Verified answer

AnSwer: When we'll toss three coins together, then the total number of Outcomes would be 8. (HHH, HHT, THH, HTH, THT, TTH, TTT, HTT)

» To Calculate the probability of any Event ( E ) the formula is Given by :

• Probability = (No. of favourable Outcomes/ Total no. of Outcomes.)

━━━━━━━━━━━━━━━━━━━━━━

⌑ The probability of Getting Exactly One Head:

• Number of favourable Outcomes are (THT, TTH, HTT).
• And, Total number of Outcomes are 8.

No. of favourable Outcomes/Total no. of Outcomes = ⅜

∴ The Probability of Getting Exactly One Head is ⅜.

⠀⠀⠀⠀

⌑ The probability of Getting Atmost two Heads:

• Number of favourable Outcomes are (HHH, HHT, THH, HTH).
• And, Total number of Outcomes are 8.

No. of favourable Outcomes/Total no. of Outcomes = ½.

∴ The Probability of Getting Atmost two Heads is ½.

⠀⠀⠀⠀

⌑ The probability of Getting Atleast one head and one tail:

• Number of favourable Outcomes are (HHT, HTH, THH, TTH, THT, HTT).
• And, Total number of Outcomes are 8.

No. of favourable Outcomes/Total no. of Outcomes = ¾

∴ The Probability of Getting Atleast one head and one tail is ¾.

⠀⠀⠀⠀

⌑ The probability of Getting No tail:

• Number of favourable Outcome (HHH)
• And, Total number of Outcomes are 8.

No. of favourable Outcomes/Total no. of Outcomes = ⅛

∴ The Probability of Getting No tail is ⅛.

━━━━━━━━━━━━━━━━━━━━━━━━━━

Three coins are tossed together. Find the probability of getting

1. Exactly one head

2. At most two heads

3. At least one head and one tail

4. No tail

Total no. of outcomes = 8 (H,H,H) , (H,H,T) , (H,T,H) , (H,T,T) , (T,H,H) , (T,H,T) , (T,T,H) , (T,T,T)

No. of favourable outcomes = 3 (H,T,T) , (T,H,T) , (T,T,H)

No. of favourable outcomes = 4 (H,H,H) , (H,H,T) , (H,T,H) , (T,H,H)

No. of favourable outcomes = 6 (H,H,T) , (H,T,H) , (H,T,T) , (T,H,H) , (T,H,T) , (T,T,H)

No. of favourable outcomes = 1 (H,H,H)