Answer:
This is your answer.
Hope it will help you..
Let the number of hen be x and number of cow be y
from question
x+y=48 ------------1
Again from question
2x+4y=140 ---------2 (since hen has 2 feet and cows have 4 feet)
On multiplying equation 1 by 2
2x+2y=96 -----------3
On subtracting eqn 3 from eqn 2,we get
2x+4y =140
2x+2y =96
- - -
-----------------
2y = 44
y = 44/2
= 22
On putting y=22 in eqn 1
x+22 = 48
x = 48-22
= 26
Hence no. of hens =26
and number of cows =22
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Answers & Comments
Answer:
This is your answer.
Hope it will help you..
Answer:
Let the number of hen be x and number of cow be y
from question
x+y=48 ------------1
Again from question
2x+4y=140 ---------2 (since hen has 2 feet and cows have 4 feet)
On multiplying equation 1 by 2
2x+2y=96 -----------3
On subtracting eqn 3 from eqn 2,we get
2x+4y =140
2x+2y =96
- - -
-----------------
2y = 44
y = 44/2
= 22
On putting y=22 in eqn 1
x+22 = 48
x = 48-22
= 26
Hence no. of hens =26
and number of cows =22