there are two holes one each along the opposite sides of wide rectangular tank.the cross section of each hole is 0.01 m and the vertical distance between two holes is one metre.the tank is filled with water the net force on the tank in newton when the water flows out of the holes is ( density of water = 1000 kgm^-3)
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We first calculate the total volume of water flowing out of the tank.Volume = Cross sectional area × length.
Volume =0.01 × 10 =0.1m³
Given density, we can get the mass.
Mass = Density × Volume.
Mass = 0.1 × 1000 =100kgs.
Force = Mass × Acceleration
Taking acceleration due to gravity :
a = 9.8m/s²
Force = 100 × 9.8 =980N
The force acting on the water is thus 980N.