Answer:
Let a, b, and c be the points scores by the 3 players. They scored a total of 70 points:
a + b + c = 70
Player A scored twice as many as player b: a = 2b
and 10 fewer than player C: a = c - 10. So c = a+10 = 2b+10
2b + b + (2b+10) = 70
5b + 10 = 70
5b = 60
b = 12 points
a = 2b = 24 points
c = a+10 = 24 + 10 = 34 points
12 + 24 + 34 = 70
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Answers & Comments
Answer:
Let a, b, and c be the points scores by the 3 players. They scored a total of 70 points:
a + b + c = 70
Player A scored twice as many as player b: a = 2b
and 10 fewer than player C: a = c - 10. So c = a+10 = 2b+10
a + b + c = 70
2b + b + (2b+10) = 70
5b + 10 = 70
5b = 60
b = 12 points
a = 2b = 24 points
c = a+10 = 24 + 10 = 34 points
12 + 24 + 34 = 70