There are 100 people in a room, out of which exactly 99% are mathematicians. How many mathematicians must leave the room to bring down the percentage of mathematicians in the rooms to exactly 98%?
Pls explain properly
ASAP
Pls explain properly
ASAP
Answers & Comments
Answer:
So the number of mathematicians in the room are 99% of the 100 people
In equation form this can be written as : (99/100) * 100
= 99 mathematicians in the room.
Let the number of mathematicians who left be 'x'
So, number of people who are still in the room will be 100-x
The number of mathematicians who are still in the room will be 99-x
So, for the percentage of mathematicians in the room to be 98%,
= (99-x)/(100-x) should be equal to 98%.
= (99-x)/(100-x) = 98/100
= 100(99-x) = 98(100-x)
= 9900 - 100x = 9800 - 98x
= 2x = 100
x = 100/2 = 50 mathematicians
50 Mathematicians should leave the room to bring down the percentage of mathematicians in the rooms to exactly 98%.