Theorem 8.1:If a line is drawn parallel to one side of a triangle to intersect. Given: A triangle ABC in which DE||BC. To prove:AD by DB =AE by EC...
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Answer:
AD/DB = AE/EC
Step-by-step explanation:
In triangles ADE and triangle ABC,
∠ADE = ∠ABC {Corresponding angles}
∠AED = ∠ACB {Corresponding angles}
∠A=∠A {Common angle}
Therefore, triangle ADE is similar to triangle ABC
Therefore, AD/AB = AE/EC