[tex]let \: the \: zeroes \: be \: 2x \: and \: 3x \: respectively \\ given \: 2x + 3x \: = 27 \\ 5x = 27 \\ x = 27 \div 5 \\ x = 5.4 \\ so \: the \: numbers \: are \: 2(5.4) \: = 10.8 \: and \: 3(5.4) \: = 16.2\: respectively \\ \\ we \: have \: to \: find \: their \: product \: which \: is \: equal \: to \: 16.2 \times 10.8 = 174.96[/tex]
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[tex]let \: the \: zeroes \: be \: 2x \: and \: 3x \: respectively \\ given \: 2x + 3x \: = 27 \\ 5x = 27 \\ x = 27 \div 5 \\ x = 5.4 \\ so \: the \: numbers \: are \: 2(5.4) \: = 10.8 \: and \: 3(5.4) \: = 16.2\: respectively \\ \\ we \: have \: to \: find \: their \: product \: which \: is \: equal \: to \: 16.2 \times 10.8 = 174.96[/tex]
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HEY! Your Answer is in the Attachment ♥️