The wave number of the limiting line in Lyman series of hydrogen is 109678 cm . The wave
number of the limiting line in Balmer series of He would be -
(A) 54839 cm (B) 219356 cm? (C) 109678 cm (D) 438712 cm? [C]
The energy of an electron in the first orbit of H-atom is - 13,6 eV. The possible energy values
number of the limiting line in Balmer series of He would be -
(A) 54839 cm (B) 219356 cm? (C) 109678 cm (D) 438712 cm? [C]
The energy of an electron in the first orbit of H-atom is - 13,6 eV. The possible energy values
Answers & Comments
Answer:
the answer is (B) 219356
Explanation:
because in spectral lines there are four series lyman, Balmer, Paschen Brackett Pfund Lyman engery levels are form 1,2,3----- and balmer are 2,3,4---- Lyman are in the uv region and balmer in the visble region so I conclude that in the spectral series the lines are started by increasing order so if Lyman series is 109678 then balmer series will be 219356 and Paschen will be 438712 and brackett will be 54839