Answer:

Given :-

• The volume of a water tank is 396 m³.
• It is 7.2 m long and 5.5 m wide.

To Find :-

• What is the depth of the tank ?

Solution :-

Let,

[tex]\mapsto \bf Depth_{(Water\: Tank)} =\: h\: m\\[/tex]

Given :

• Volume of Water Tank = 396 m³
• Length of Water Tank = 7.2 m
• Breadth of Water Tank = 5.5 m

According to the question by using the formula we get,

[tex]\small \implies \sf\boxed{\bold{Volume_{(Cuboid)} =\: Length \times Breadth \times Height}}\\[/tex]

[tex]\implies \sf 396 =\: 7.2 \times 5.5 \times h\\[/tex]

[tex]\implies \sf 396 =\: 39.6 \times h\\[/tex]

[tex]\implies \sf 396 =\: 39.6h\\[/tex]

[tex]\implies \sf \dfrac{396}{39.6} =\: h\\[/tex]

[tex]\implies \sf 10 =\: h\\[/tex]

[tex]\implies \sf\bold{h =\: 10}\\[/tex]

Hence, the depth of the tank will be :

[tex]\dag[/tex] Depth Of Water Tank :

[tex]\dashrightarrow \sf Depth_{(Water\: Tank)} =\: h\: m\\[/tex]

[tex]\dashrightarrow \sf\bold{\underline{Depth_{(Water\: Tank)} =\: 10\: m}}\\[/tex]

[tex]\small \sf\boxed{\bold{\therefore\: The\: depth\: of\: the\: water\: tank\: is\: 10\: m\: .}}\\[/tex]

.

Given :

• Volume of Tank is 396 m³ .

• Length of Tank is 7.2 m and breadth is 5.5 m .

To Find :

•Height of Tank .

Solution :

[tex]\longmapsto\tt{Length\:(l)=7.2\:m} \\ \\

\longmapsto\tt{Breadth\:(b)=5.5\:m}[/tex]

UsingFormula :

[tex]\longmapsto\tt\boxed{Volume\:of\:Cuboid=l\times{b}\times{h}}[/tex]

PuttingValues :

[tex]\longmapsto\tt{396=7.2\times{5.5}\times{h}}[/tex]

[tex]\longmapsto\tt{\dfrac{{\cancel{396}}\times{10}}{{\cancel{72}}\times{5.5}}=h}[/tex]

[tex]\longmapsto\tt{\dfrac{{\cancel{5.5}}\times{10}}{{\cancel{5.5}}}=h}[/tex]

[tex]\longmapsto\tt\bf{10\:m=h}[/tex]

So , The Height/Depth of Tank is 10 m .

[tex]\rule{250pt}{2.5pt}[/tex]

Additional Information:

[tex]\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\bf{ \pink{More \: Formulae}}}} \\ \\ \bullet\: \sf{CSA_{(cylinder)} = 2\pi \: rh}\\ \\ \bullet\: \sf{Volume_{(cylinder)} = \pi {r}^{2} h}\\ \\ \bullet\: \sf{TSA_{(cylinder)} = 2\pi \: r(r + h)}\\ \\ \bullet \: \sf{CSA_{(cone)} = \pi \: r \: l}\\ \\ \bullet \: \sf{TSA_{(cone)} = \pi \: r \: (l + r)}\\ \\ \bullet \: \sf{Volume_{(sphere)} = \dfrac{4}{3}\pi {r}^{3} }\\ \\ \bullet \: \sf{Volume_{(cube)} = {(side)}^{3} }\\ \\ \bullet \: \sf{CSA_{(cube)} = 4 {(side)}^{2} }\\ \\ \bullet \: \sf{TSA_{(cube)} = 6 {(side)}^{2} }\\ \\ \bullet \: \sf{Volume_{(cuboid)} = lbh}\\ \\ \bullet \: \sf{CSA_{(cuboid)} = 2(l + b)h}\\ \\ \bullet \: \sf{TSA_{(cuboid)} = 2(lb +bh+hl )}\\ \: \end{array} }} \end{gathered}[/tex]