Answer:
tan 40° - cot 50°
tan(90-50)° - cot 50°
cot 50° - cot 50°
0
sin 0° = cos 90° = 0
Hence, tan 40° - cot 50° = sin0° or cos90°
The value of tan40ocot50o
=tan40ocot(90o−40o)
=tan40otan40o=1
[∵cot(90o−θ)=tanθ]
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Answer:
tan 40° - cot 50°
tan(90-50)° - cot 50°
cot 50° - cot 50°
0
sin 0° = cos 90° = 0
Hence, tan 40° - cot 50° = sin0° or cos90°
Answer:
The value of tan40ocot50o
=tan40ocot(90o−40o)
=tan40otan40o=1
[∵cot(90o−θ)=tanθ]