Given:
Let the original price of the car = Rs. X
Percentage of depreciation per year = 20% Time period 2 yrs =
Price of a car after two years = Rs. 208000
(1-100)", Amount of depreciation A = P1
here A is the amount after depreciation, r is the rate of depreciation and n is time.
20 100 208000 x 1
→ 208000 = x 100 - 20 100 2
80
→ 208000 = X 100 4 2
→ 208000 = X
5
16 25 208000 = X
→ X = 208000 × 25 25 16
→ X = Rs. 325000
... Original price of the car = Rs. 325000
If you like my answer, please mark it as ✔BRAINLIEST! Good Luck and have a
nice day!! ❤Farhan❤
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer in attachment....
Given:
Let the original price of the car = Rs. X
Percentage of depreciation per year = 20% Time period 2 yrs =
Price of a car after two years = Rs. 208000
(1-100)", Amount of depreciation A = P1
here A is the amount after depreciation, r is the rate of depreciation and n is time.
20 100 208000 x 1
→ 208000 = x 100 - 20 100 2
80
→ 208000 = X 100 4 2
→ 208000 = X
5
16 25 208000 = X
→ X = 208000 × 25 25 16
→ X = Rs. 325000
... Original price of the car = Rs. 325000
If you like my answer, please mark it as ✔BRAINLIEST! Good Luck and have a
nice day!! ❤Farhan❤