Verified answer

SOLUTION:

Step 1: List the given values.

The temperature and pressure of an ideal gas at STP are 273 K and 1.00 atm, respectively.

To convert the temperature from degree Celsius to kelvin, add 273 to the temperature expressed in degree Celsius.

[tex]\begin{aligned} & P_1 = \text{1.00 atm} \\ & T_1 = \text{273 K} \\ & T_2 = 250^{\circ}\text{C} = \text{523 K} \end{aligned}[/tex]

Step 2: Calculate the final pressure by using Gay-Lussac's law.

[tex]\begin{aligned} \frac{P_1}{T_1} & = \frac{P_2}{T_2} \\ P_2T_1 & = P_1T_2 \\ \frac{P_2T_1}{T_1} & = \frac{P_1T_2}{T_1} \\ P_2 & = \frac{P_1T_2}{T_1} \\ & = \frac{(\text{1.00 atm})(\text{523 K})}{\text{273 K}} \\ & = \boxed{\text{1.92 atm}} \end{aligned}[/tex]

Hence, the final pressure of the gas is 1.92 atm.

[tex]\\[/tex]

#CarryOnLearning