Verified answer

Given :-

• Charge for first 10 km is ₹166
• For a journey of 15 km charge paid is ₹256

To find :-

• the fixed charges
• charge per km
• Amount to be payed for travelling a distance of 25 km

Solution :-

We will first calculate the fixed charges and the charges per km.

As per the first condition,

• For the first 10 km, the charge paid is 166,

So, let the fixed charge be ₹ x

Let the charge per km be ₹ y

For first 10 km charge paid is ₹ 166.

Let's represent it mathematically to get our first equation,

x + 10y = 166 -----> 1

[ x is fixed charge, which means it constant. We can't make any changes in x, so thereby, as per assumption, y is charge per km, which can vary so we can make changes in it]

As per the second condition,

• For a journey of 15 km. the charge paid is 256

Let's represent this too mathematically to get our second equation,

x + 15y = 256 ----> 2

We got our two equations, solve them via elimination method, simultaneously.

Subtract equation 2 from 1,

...x + 10y = 166

- (x + 15y = 256)

-----------------------

- 5y = -90

5y = 90

y =

y = 18

•°• Charge per km = y = ₹ 18

Substitute, y = 18 in equation 1,

x + 10y = 166

x + 10 (18) = 166

x + 180 = 166

x = 166 - 180

x = - 14

As, x = charge (fixed) it cannot be negative,

•°• x = 14

•°• Fixed charge = x = ₹ 14

Now, we have to find the charge payed for a journey of 25 km

We will add the fixed charge by 25 times the charge per km,

For 25 km,

x + 25y

14 + 25(18)

14 + 450 = 464

•°• Charge payed for a journey of 25 km is ₹ 464