Answer:

96

Step-by-step explanation:

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Answer:

let x the first number

let y the second number

the sum of two numbers is 128

x+y=128 ----> eq.1

the first number is 3 times bigger than 2nd number

x=3y ------> eq.2

substitute eq.2 to eq.1

3y+y = 128

4y=128

y=128/4

y=32

so that

x=3y

x=3(32)

x=96 ----> answer.