Answer:
Step-by-step explanation:
let the no. be x,y
x+y = 60 ....i
and the sum of their reciprocals .i.e
1/x + 1/y = 1/13
x+y/xy = 1/13
13(x + y) = xy
13(60) = xy
xy = 780
x = 60 - y
(60 - y)y = 780
-y^2 +60y - 780 = 0
y^2 - 60y + 780 = 0
By Quadratic Formula,
a = 1, b = -60 , c = 780
y = 60 ± √3600 -3120 / 2
y = 60 ± 22/2
y = 82/2 = 41
x = 60 - 41 = 19
or
y = 60 - 22/2
y = 19
x = 60 - 19 = 41
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Verified answer
Answer:
Step-by-step explanation:
let the no. be x,y
x+y = 60 ....i
and the sum of their reciprocals .i.e
1/x + 1/y = 1/13
x+y/xy = 1/13
13(x + y) = xy
13(60) = xy
xy = 780
x = 60 - y
(60 - y)y = 780
-y^2 +60y - 780 = 0
y^2 - 60y + 780 = 0
By Quadratic Formula,
a = 1, b = -60 , c = 780
y = 60 ± √3600 -3120 / 2
y = 60 ± 22/2
y = 82/2 = 41
x = 60 - 41 = 19
or
y = 60 - 22/2
y = 19
x = 60 - 19 = 41
HOPE I HELPED YOU
PLZ MARK ME AS BRAINLIEST