Step-by-step explanation:
Let the three numbers be x−1,x and x+1
⇒x−1+x+x+1=81
⇒3x=81
∴x= 81/3
=27
Let the first integer be x
Then, second integer = x + 1
Third integer = x + 2
The total sum = 81
So, we can can say that
x + x + 1 + x + 2 = 81
→3x + 3 = 81
→3x = 81 - 3
→3x = 78
→x = 78/3
→x = 26
Therefore,
Integer 1 : x = 26
Integer 2 : x + 1 = 26 + 1 = 27
Integer 3 : x + 2 = 26 + 2 = 28
Therefore, the three consecutive integers are 26, 27 and 28.
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Verified answer
Step-by-step explanation:
Let the three numbers be x−1,x and x+1
⇒x−1+x+x+1=81
⇒3x=81
∴x= 81/3
=27
Let the first integer be x
Then, second integer = x + 1
Third integer = x + 2
The total sum = 81
So, we can can say that
x + x + 1 + x + 2 = 81
→3x + 3 = 81
→3x = 81 - 3
→3x = 78
→x = 78/3
→x = 26
Therefore,
Integer 1 : x = 26
Integer 2 : x + 1 = 26 + 1 = 27
Integer 3 : x + 2 = 26 + 2 = 28
Therefore, the three consecutive integers are 26, 27 and 28.
________________________________
Happy learning
ᖶᕼᗩᘉᖽᐸ ᖻᓍᑘ:D