Answer:
Those multiples are 7 ,14, 21 and 28
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Answer:
Those multiples are 7 ,14, 21 and 28
Please mark me as the brainliest answer
[tex]Four \: Consecutive \: multiple \\ are \\ \\ 7n ,7(n + 1) ,7(n + 2) ,7(n + 3)[/tex]
[tex] \\ [/tex]
[tex]7n + 7n + 7 + 7n + 14n + 7n + 21 = 70 \\ \\ 28n + 42 = 70 \\ \\ 28n = 70 - 42 \\ \\ 28n = 28 \\ \\ n = \frac{28}{28} \\ \\ n = 1[/tex]
[tex] \\ [/tex]
[tex] = 7(n + 1) \\ \\ = 7(1 + 1) \\ \\ = 7(2) \\ \\ = 14[/tex]
[tex] = 7(n + 2) \\ \\ = 7(1 + 2) \\ \\ = 7(3) \\ \\ = 21[/tex]
[tex] = 7(n + 3) \\ \\ = 7(1 + 3) \\ \\ = 7(4) \\ \\ = 28[/tex]
[tex] \\ [/tex]
[tex] = 7 ,14 ,21 ,28[/tex]