Verified answer

Answer:

sum of area of the squares of sides '3a' and '3b' will be 9 ( a² + b² )  

Step-by-step explanation:

given that :

there are two squares ,

side length of a first square is 3a

side length of a second square is 3b

area of first square is (side)² = (3a)² = 9a²

area of second square = (3b)² = 9b²

sum of area of two given squares is (9a² + 9b² )

sum of area of the squares of sides 3a and 3b will be  9 ( a² + b² )  

Answer is 9(A²+B²)

Area of square with side 3A = 9A²

Area of square with side 3B = 9B²

Sum of the Area = 9A² + 9B² = 9(A²+B²)