Step-by-step explanation:

Given units digit is x and tens digit is y

Hence the two digit number = 10y + x

Number obtained by reversing the digits = 10x + y

Given that sum of a two digit number and the number obtained by reversing the order of its digits is 121.

Then (10y+x)+(10x+y)=121

⇒10y+x+10x+y=121

⇒11x+11y=121

⇒x+y=11

Thus the required linear equation is x + y = 11.

Verified answer

• 65 + 56 = 121

Let no. be t5

• reverse will be 5t

• [tex]t \times 10+5+5 \times 10+t[/tex]

• =11t+55=121

• [tex] \Rightarrow \: 11t=66[/tex]

• =>t=6

• So no.=65

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