Answer:
Let the first term be (a – 2d)
⇒ Second term = (a – d)
⇒ Third term = a
⇒ Fourth term = (a + d)
⇒ Fifth term = (2a + d)
According to the question
a – 2d + a – d + a + a + d + a + 2d = 75
⇒ 5a = 75
⇒ a = 75/5
⇒ a = 15
∴ The third term is 15.
Step-by-step explanation:
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Let a be the first term and d be the common difference of the given A.P. It is given that
a
3
=7 and a7
=3a3 +2
a+2d=7 and a+6d=3(a+2d)+2
a+2d=7 and a=−1
a=−1,d=4
I am crystii wbu
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Verified answer
Answer:
Let the first term be (a – 2d)
⇒ Second term = (a – d)
⇒ Third term = a
⇒ Fourth term = (a + d)
⇒ Fifth term = (2a + d)
According to the question
a – 2d + a – d + a + a + d + a + 2d = 75
⇒ 5a = 75
⇒ a = 75/5
⇒ a = 15
∴ The third term is 15.
Step-by-step explanation:
I am back (:
Answer:
Let a be the first term and d be the common difference of the given A.P. It is given that
a
3
=7 and a7
=3a3 +2
a+2d=7 and a+6d=3(a+2d)+2
a+2d=7 and a=−1
a=−1,d=4
I am crystii wbu