The sum of four consecutive even numbers is 200. Find the four numbers.
Representation:
1st integer: x
2nd integer: x + 2
3rd integer: x + 4
4th integer: x + 6
Equation:
x + x + 2 + x + 4 + x + 6 = 212
x + x + 2 + x + 4 + x + 6 = 212
4x + 2 + 4 + 6 = 212
4x + 12 = 212
4x = 212 - 12
4x = 200
x = 200/4
x = 50
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In your question, Yuju, you were finding the four numbers. Since the value of x is 50 and it is even, therefore the four consecutive even numbers are 50, 52, 54, and 56.
Answers & Comments
The sum of four consecutive even numbers is 200. Find the four numbers.
Representation:
Equation:
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In your question, Yuju, you were finding the four numbers. Since the value of x is 50 and it is even, therefore the four consecutive even numbers are 50, 52, 54, and 56.
Verified answer
Answer: 9, 10 ,11 and 12.
EXPLANATION:
Let assume the first number of four consecutive numbers is a then the second number is a + 1 , third number is a + 2 and fourth number is a + 3.