Answer:
3587
Step-by-step explanation:
The given series appears to be an arithmetic progression where the first term (a) is 1, the common difference (d) is 3 (4 - 1), and the last term (an) is 49.
The formula for the sum of an arithmetic series is:
Sum (S) = (n/2) * [2a + (n - 1)d]
Let's plug in the values:
n = 49 (since there are 49 terms)
a = 1
d = 3
Sum (S) = (49/2) * [2*1 + (49 - 1)*3]
Sum (S) = (49/2) * [2 + 48*3]
Sum (S) = (49/2) * [2 + 144]
Sum (S) = (49/2) * 146
Sum (S) = 49 * 73
Sum (S) = 3587
So, the sum of the given series is equal to 3587.
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Answers & Comments
Answer:
3587
Step-by-step explanation:
The given series appears to be an arithmetic progression where the first term (a) is 1, the common difference (d) is 3 (4 - 1), and the last term (an) is 49.
The formula for the sum of an arithmetic series is:
Sum (S) = (n/2) * [2a + (n - 1)d]
Let's plug in the values:
n = 49 (since there are 49 terms)
a = 1
d = 3
Sum (S) = (49/2) * [2*1 + (49 - 1)*3]
Sum (S) = (49/2) * [2 + 48*3]
Sum (S) = (49/2) * [2 + 144]
Sum (S) = (49/2) * 146
Sum (S) = (49/2) * 146
Sum (S) = 49 * 73
Sum (S) = 3587
So, the sum of the given series is equal to 3587.