Answer:

Smallest number in the ap(a) = -6.2

Step-by-step explanation:

S10 = 10

d = 1.6

Sn = n/2[2a+(n-1)d]

Substituting values required

10 = 10/2[2a+(9)1.6]

10 = 5[2a+14.4]

10 = 10a+72

-62 = 10a

a = -62/10

a = -6.2

The smallest no, the first term of the AP is -6.2

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