The stopping potential for electrons emitted from a photosensitive surface illuminated by light of wavelength 310 nm is 0.6V. When the incident wavelength is changed to a new value, the stopping potential is 1.2V. The new wavelength is
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Explanation:
From the photoelectric effect equation
hc/λ = ϕ + evs
where Vs is the stopping potential and ϕ is work function of the metal.
So, evs1 = hc/λ1 – ϕ ……(i)
evs2 = hc/λ2 – ϕ …..(ii)
Subtract equation (i) from equation (ii)
evs1 – evs2 = hc/λ1– hc/λ2
vs1 – vs2 = (hc/e) (1/λ1 – 1/λ2)
(0.710 – 1.43) = 1240 (1/491 – 1/λ2)
(because hc = 1240 eV nm)
-0.72/1240 = 1/491 – 1/λ2
1/λ2 = 1/491 + 0.72/1240
1/λ2 = 0.00203 + 0.00058
1/λ2 = 0.00261
λ2 = 383.14
λ2 ≃ 382
Answer:
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Write an application to the Chief Engineer, Electricity Department complaining about the frequent power cuts in your area. Write how it is affecting the students as the exams are approaching. Also mention how the other people are being affected.