Answer:
Well, let us suppose three natural numbers i.e. a,b and c. And choose c such that c is a multiple of a and b. Then the relation will be
a^2+b^2+(a.b)^2=x^2. Here x can be written as a*b+1. so the given equation becomes.
a^2+b^2+(a*b)^2=[(a*b)+1]^2. And a-b= +- 1.
For e.g.
2^2+3^2+6^2=7^2
3^2+4^2+12^2=13^2
and so on...
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Answers & Comments
Answer:
Well, let us suppose three natural numbers i.e. a,b and c. And choose c such that c is a multiple of a and b. Then the relation will be
a^2+b^2+(a.b)^2=x^2. Here x can be written as a*b+1. so the given equation becomes.
a^2+b^2+(a*b)^2=[(a*b)+1]^2. And a-b= +- 1.
For e.g.
2^2+3^2+6^2=7^2
3^2+4^2+12^2=13^2
and so on...