The sides of a triangular field are 775 m, 1050 m, 1125m. If this field is sold ...

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August 2021 2 29 Report

The sides of a triangular field are 775 m, 1050 m, 1125m. If this field is sold at the rate of Rs.1000 per hectare, find its selling price.

akmbaul2055

Answer:

Area of the triangle=

s.(s−a)(s−b)(s−c)

(by heron's formula)

where s=

(a+b+c)

a=975m, b=1050m, c=1125m

∴s=1575m

Area=

1575(1575−975)(1575−1050)(1575−1125)

⇒472500m

1hectare=10,000m

∴472500m

=47.25hectares

⇒ selling price of the field will be 47.25hectares×1000

⇒=47250Rs

plz mrk as brainliest

brainlyehsanul

Step-by-step explanation:

Given :

a = 975m

b = 1050m

c = 1125m

Find :

Its selling price.

Solution :

$s = \frac{a + b + c}{2}$

$s = \frac{975 + 1050 + 1125}{2}$

$s = \frac{3150}{2}$

$s = 1575 \: \: m.$

Area of a triangular field

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{1575(1575 - 975)(1575 - 1050)(1575 - 1125)}$

$\sqrt{1575 \times 600 \times 525 \times 450}$

$\sqrt{525 \times 3 \times 2 \times 2 \times 2 \times 5 \times 5 \times 3 \times 525 \times 2 \times 5 \times 5 \times 3 \times 3}$

$525 \times 3 \times 2 \times 2 \times 3 \times 5 \times 5$

$525 \times 900$

$472500 \: \: m.$

Selling price of the field in hectare

$\frac{472500 \times 1000}{10000}$

₹47250.

Hence :

Selling price of the field is ₹47250.

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