Given :
[tex]~[/tex]
To Find :
[tex]{\rule{190pt}{2pt}}[/tex]
SolutioN :
[tex]{\bf{\dag}}[/tex] Formula Used :
[tex]\qquad\star~{\underline{\boxed{\pmb{\sf{Area~of~ trapezium~=~\dfrac{1}{2}~×~ (sum~ of~ parallel ~sides)~×~height}}}}}[/tex]
[tex]{\bf{\dag}}[/tex] According to the Question :
[tex]\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(1~+~1.2\bigg)~×~0.8}}[/tex]
[tex]\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(2.2\bigg)~×~0.8}}[/tex]
[tex]\qquad{\sf:\implies{Area~=~\dfrac{12}{20}~×~\dfrac{8}{10}}}[/tex]
[tex]\qquad{\sf:\implies{Area~=~\cancel\dfrac{176}{200}}}[/tex]
[tex]\qquad:\implies{\pmb{\underline{\boxed{\pink{\frak{Area~=~0.88 }}}}}}[/tex]★
Hence,
[tex]\qquad[/tex] ∴ The area of trapezium is 0.88m².
Answer:
The shape of the top surface of a table is a trapezium.
~
Area of trapezium ?
{\rule{190pt}{2pt}}
Let us assume that, the area of trapezium be x.
{\bf{\dag}}† Formula Used :
\qquad\star~{\underline{\boxed{\pmb{\sf{Area~of~ trapezium~=~\dfrac{1}{2}~×~ (sum~ of~ parallel ~sides)~×~height}}}}}⋆
Area of trapezium =
2
1
× (sum of parallel sides) × height
{\bf{\dag}}† According to the Question :
\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(1~+~1.2\bigg)~×~0.8}}:⟹Area =
(1 + 1.2) × 0.8
\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(2.2\bigg)~×~0.8}}:⟹Area =
(2.2) × 0.8
\qquad{\sf:\implies{Area~=~\dfrac{12}{20}~×~\dfrac{8}{10}}}:⟹Area =
20
12
×
10
8
\qquad{\sf:\implies{Area~=~\cancel\dfrac{176}{200}}}:⟹Area =
200
176
\qquad:\implies{\pmb{\underline{\boxed{\pink{\frak{Area~=~0.88 }}}}}}:⟹
Area = 0.88
★
\qquad ∴ The area of trapezium is 0.88m².
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Answers & Comments
Verified answer
Given :
[tex]~[/tex]
To Find :
[tex]~[/tex]
[tex]{\rule{190pt}{2pt}}[/tex]
SolutioN :
[tex]~[/tex]
[tex]{\bf{\dag}}[/tex] Formula Used :
[tex]\qquad\star~{\underline{\boxed{\pmb{\sf{Area~of~ trapezium~=~\dfrac{1}{2}~×~ (sum~ of~ parallel ~sides)~×~height}}}}}[/tex]
[tex]~[/tex]
[tex]{\bf{\dag}}[/tex] According to the Question :
[tex]~[/tex]
[tex]\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(1~+~1.2\bigg)~×~0.8}}[/tex]
[tex]~[/tex]
[tex]\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(2.2\bigg)~×~0.8}}[/tex]
[tex]~[/tex]
[tex]\qquad{\sf:\implies{Area~=~\dfrac{12}{20}~×~\dfrac{8}{10}}}[/tex]
[tex]~[/tex]
[tex]\qquad{\sf:\implies{Area~=~\cancel\dfrac{176}{200}}}[/tex]
[tex]~[/tex]
[tex]\qquad:\implies{\pmb{\underline{\boxed{\pink{\frak{Area~=~0.88 }}}}}}[/tex]★
[tex]~[/tex]
Hence,
[tex]~[/tex]
[tex]\qquad[/tex] ∴ The area of trapezium is 0.88m².
[tex]~[/tex]
[tex]{\rule{190pt}{2pt}}[/tex]
Answer:
Given :
The shape of the top surface of a table is a trapezium.
~
To Find :
Area of trapezium ?
~
{\rule{190pt}{2pt}}
SolutioN :
Let us assume that, the area of trapezium be x.
~
{\bf{\dag}}† Formula Used :
\qquad\star~{\underline{\boxed{\pmb{\sf{Area~of~ trapezium~=~\dfrac{1}{2}~×~ (sum~ of~ parallel ~sides)~×~height}}}}}⋆
Area of trapezium =
2
1
× (sum of parallel sides) × height
Area of trapezium =
2
1
× (sum of parallel sides) × height
~
{\bf{\dag}}† According to the Question :
~
\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(1~+~1.2\bigg)~×~0.8}}:⟹Area =
2
1
(1 + 1.2) × 0.8
~
\qquad{\sf:\implies{Area~=~\dfrac{1}{2}\bigg(2.2\bigg)~×~0.8}}:⟹Area =
2
1
(2.2) × 0.8
~
\qquad{\sf:\implies{Area~=~\dfrac{12}{20}~×~\dfrac{8}{10}}}:⟹Area =
20
12
×
10
8
~
\qquad{\sf:\implies{Area~=~\cancel\dfrac{176}{200}}}:⟹Area =
200
176
~
\qquad:\implies{\pmb{\underline{\boxed{\pink{\frak{Area~=~0.88 }}}}}}:⟹
Area = 0.88
Area = 0.88
★
~
Hence,
~
\qquad ∴ The area of trapezium is 0.88m².
~
{\rule{190pt}{2pt}}