In tringle ABD,tan 600 =ABBD√3=hx∴x=h√3 ......(

ABBC⇒ 1√3 =hx+40⇒x+40=√3h∴ h√3 +40=√3h [from equ..(1)]⇒h+40√3=3h⇒2h=40√3

∴h=20√3

∴ The height of a tower is 20√3}

Step-by-step explanation:

1. The shadow of a tower standing on level ground is found to be 40 m longer when the Sun’s altitude is 30° than when it is 60°. Find the height of the tower