Answer:
Time period of stationary orbit T=24 hrs=24×60×60 s
Angular velocity ω=
T
2π
=
24×60×60
Acceleration =ω
2
R
e
=(
)
×6.4×10
6
=0.22 ms
−2
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Answer:
Time period of stationary orbit T=24 hrs=24×60×60 s
Angular velocity ω=
T
2π
=
24×60×60
2π
Acceleration =ω
2
R
e
=(
24×60×60
2π
)
2
×6.4×10
6
=0.22 ms
−2