In XeF₄,total number of valence electrons of Xe=8,4 electrons are shared with 4F atoms ,4 electrons are left hence 2 lone pairs. In XeF₆,total number of valence electrons of Xe=8,6 electrons are shared with 6F atoms ,2 electrons are left hence 1 lone pair.
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Explanation:
In XeF₄,total number of valence electrons of Xe=8,4 electrons are shared with 4F atoms ,4 electrons are left hence 2 lone pairs. In XeF₆,total number of valence electrons of Xe=8,6 electrons are shared with 6F atoms ,2 electrons are left hence 1 lone pair.
Explanation:
9 : 14
As the question asked total pairs , count the lone pairs of fluorine also
XeF2
3+6
XeF4
2+12