Answer:
Step-by-step explanation:
__________________________
Let the radii of the circles be r1 & r2 respectively.
Then, their circumferences are 2πr1 & 2πr2, respectively.
So, their ratio=2πr1:2πr2=r1:r2.
Again, the areas of the circles are π(r1)2 & π(r2)2.
Then, their ratio =π(r1)2:π(r2)2=(r1)2:(r2)2=16:25 ...(given).
∴(r1):(r2)=√16:25
=±(4:5)
We reject the negative value of r's since the radius is a length.
∴(r1):(r2)=(4:5).
5
The area of smaller painting is 3.14×4²= 50.24 (πr²)
let the area of larger painting be 3.14×r²
then
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Answers & Comments
Answer:
Step-by-step explanation:
__________________________
Let the radii of the circles be r1 & r2 respectively.
Then, their circumferences are 2πr1 & 2πr2, respectively.
So, their ratio=2πr1:2πr2=r1:r2.
Again, the areas of the circles are π(r1)2 & π(r2)2.
Then, their ratio =π(r1)2:π(r2)2=(r1)2:(r2)2=16:25 ...(given).
∴(r1):(r2)=√16:25
=±(4:5)
We reject the negative value of r's since the radius is a length.
∴(r1):(r2)=(4:5).
__________________________
Answer:
5
Step-by-step explanation:
The area of smaller painting is 3.14×4²= 50.24 (πr²)
let the area of larger painting be 3.14×r²
then