Let have a polynomial P = aX^2+bX+c = a(X-r)(X-s), here we choose to denote the roots of the polynome by r and s (which are eventually the same). By expanding we obtain :
P = aX² -a(r+s)X + ars
By identification we have b = -a(r+s) and c = ars.
In our case we obtain that P is of the form : aX² -3aX = aX(X-3) where a could be any non zero real number.
Answers & Comments
Answer:
y²-3y=0
Step-by-step explanation:
y² -(0+3)y + 0(3)=0
y²-3y=0
Verified answer
Answer:
Step-by-step explanation:
Let have a polynomial P = aX^2+bX+c = a(X-r)(X-s), here we choose to denote the roots of the polynome by r and s (which are eventually the same). By expanding we obtain :
P = aX² -a(r+s)X + ars
By identification we have b = -a(r+s) and c = ars.
In our case we obtain that P is of the form : aX² -3aX = aX(X-3) where a could be any non zero real number.