The integers are 14 and 15, or the integers are –15 and –14.
The integers are 14 and 15, or the integers are –15 and –14. (NOTE: You must give both parts of the answer.) To set up this problem, let x = the first integer. Then x + 1 = the next consecutive integer. The equation is x(x + 1) = 210.
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers.
2) Call the two consecutive integers "n" and "n+1", and solve the equation:
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Step-by-step explanation:
The integers are 14 and 15, or the integers are –15 and –14.
The integers are 14 and 15, or the integers are –15 and –14. (NOTE: You must give both parts of the answer.) To set up this problem, let x = the first integer. Then x + 1 = the next consecutive integer. The equation is x(x + 1) = 210.
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers.
2) Call the two consecutive integers "n" and "n+1", and solve the equation:
n(n+1)=210