Solution :
Here , the present price of the machine is Rs. 100, 000 .
The price decreases regularly at a rate of 10% per annum .
We need to find what will be it's price after 3 years .
So , in the present , the price is Rs. 100,000
The next year , it will be decreased by 10%
Or in other terms , it will be 90% of what it was previously ; 90% of the price in the previous year.
So ,
In Year 1 :
New Price -
=> 90% of orginal price
=> 90% of 100,000
=> 90 × 1000
=> 90,000
In the second year the same thing will repeat
New price = 90% of what it was in the first year
=> 90% of 90,000
=> 90 × 900
=> 81, 000
In the third year
Price -
=> 90% of the price in the second year
=> 90% of 81,000
=> 90 × 810
=> 72900
Thus , the required price after 3 years is 72,900.
This is the required answer.
___________________________________________
Answer:
where,
Given :
According to the question by using the formula we get,
⇒
➠
The price of that machine after 3 years is Rs 72900 .
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Verified answer
Solution :
Here , the present price of the machine is Rs. 100, 000 .
The price decreases regularly at a rate of 10% per annum .
We need to find what will be it's price after 3 years .
So , in the present , the price is Rs. 100,000
The next year , it will be decreased by 10%
Or in other terms , it will be 90% of what it was previously ; 90% of the price in the previous year.
So ,
In Year 1 :
New Price -
=> 90% of orginal price
=> 90% of 100,000
=> 90 × 1000
=> 90,000
In the second year the same thing will repeat
New price = 90% of what it was in the first year
=> 90% of 90,000
=> 90 × 900
=> 81, 000
In the third year
Price -
=> 90% of the price in the second year
=> 90% of 81,000
=> 90 × 810
=> 72900
Thus , the required price after 3 years is 72,900.
This is the required answer.
___________________________________________
Answer:
Given :-
To Find :-
Formula Used :-
where,
Solution :-
Given :
According to the question by using the formula we get,
⇒![\sf A\: =\: 100000\bigg(1 - \dfrac{10}{100}\bigg)^{3} \sf A\: =\: 100000\bigg(1 - \dfrac{10}{100}\bigg)^{3}](https://tex.z-dn.net/?f=%5Csf%20A%5C%3A%20%3D%5C%3A%20100000%5Cbigg%281%20-%20%5Cdfrac%7B10%7D%7B100%7D%5Cbigg%29%5E%7B3%7D)
⇒![\sf A\: =\: 100000\bigg(1 - \dfrac{\cancel{10}}{\cancel{100}}\bigg)^{3} \sf A\: =\: 100000\bigg(1 - \dfrac{\cancel{10}}{\cancel{100}}\bigg)^{3}](https://tex.z-dn.net/?f=%5Csf%20A%5C%3A%20%3D%5C%3A%20100000%5Cbigg%281%20-%20%5Cdfrac%7B%5Ccancel%7B10%7D%7D%7B%5Ccancel%7B100%7D%7D%5Cbigg%29%5E%7B3%7D)
⇒![\sf A\: =\: 100000\bigg(1 - \dfrac{1}{10}\bigg)^{3} \sf A\: =\: 100000\bigg(1 - \dfrac{1}{10}\bigg)^{3}](https://tex.z-dn.net/?f=%5Csf%20A%5C%3A%20%3D%5C%3A%20100000%5Cbigg%281%20-%20%5Cdfrac%7B1%7D%7B10%7D%5Cbigg%29%5E%7B3%7D)
⇒![\sf A\: =\: 100000\bigg(\dfrac{9}{10}\bigg)^{3} \sf A\: =\: 100000\bigg(\dfrac{9}{10}\bigg)^{3}](https://tex.z-dn.net/?f=%5Csf%20A%5C%3A%20%3D%5C%3A%20100000%5Cbigg%28%5Cdfrac%7B9%7D%7B10%7D%5Cbigg%29%5E%7B3%7D)
⇒![\sf A\: =\: 100000 \times \dfrac{9}{10} \times \dfrac{9}{10} \times \dfrac{9}{10} \sf A\: =\: 100000 \times \dfrac{9}{10} \times \dfrac{9}{10} \times \dfrac{9}{10}](https://tex.z-dn.net/?f=%5Csf%20A%5C%3A%20%3D%5C%3A%20100000%20%5Ctimes%20%5Cdfrac%7B9%7D%7B10%7D%20%5Ctimes%20%5Cdfrac%7B9%7D%7B10%7D%20%5Ctimes%20%5Cdfrac%7B9%7D%7B10%7D)
⇒![\sf A\: =\: \dfrac{72900000}{1000} \sf A\: =\: \dfrac{72900000}{1000}](https://tex.z-dn.net/?f=%5Csf%20A%5C%3A%20%3D%5C%3A%20%5Cdfrac%7B72900000%7D%7B1000%7D)
⇒![\sf A\: =\: \dfrac{\cancel{72900000}}{\cancel{1000}} \sf A\: =\: \dfrac{\cancel{72900000}}{\cancel{1000}}](https://tex.z-dn.net/?f=%5Csf%20A%5C%3A%20%3D%5C%3A%20%5Cdfrac%7B%5Ccancel%7B72900000%7D%7D%7B%5Ccancel%7B1000%7D%7D)
➠![\sf\red{A\: =\: Rs\: 72900} \sf\red{A\: =\: Rs\: 72900}](https://tex.z-dn.net/?f=%5Csf%5Cred%7BA%5C%3A%20%3D%5C%3A%20Rs%5C%3A%2072900%7D)