Given :-

• The present ages of Meeta and Aarushi are in the ratio 5:4.
• Eight years from now, the ratio of their ages will be 6:5.

To Find :-

• Their Present Ages

Solution :-

⟼ Let the Present age of Meeta be 5x

⟼ Let the Present age of Aarushi be 4x

After 8 years :

⟼ After 8 years, age of Meeta = 5x + 8

⟼ After 8 years, age of Aarushi = 4x + 8

According to the Question :

➞ 5x + 8 / 4x + 8 = 6/5

➞ 5 (5x + 8) = 6 (4x + 8)

➞ 25x + 40 = 24x + 48

➞ 25x - 24x = 48 - 40

➞ x = 8

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Therefore :

• Present age of Meeta = 5x = 5 × 8 = 40years
• Present age of Aarushi = 4x = 4 × 8 = 36years

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