Answer:
increases by 10.5% every year.
Also, the present population is 7,95,600.
To find out: Population of the town a year ago.
Let the population of the town a year ago be x.
∴ Population 1 years ago=
100+increase%
100
×present population
⇒x=
110.5
×795600=720000
Hence, the population of the town a year ago was 7,20,000.
mark me as brainlist
Class 11
>>Applied Mathematics
>>Basics of financial mathematics
>>Accumulation with simple and compound interest
>>The population of a town increases by 10
Question
Bookmark
The population of a town increases by 10.5% every year. If its present population is 7,95,600, what was it a year ago.
Medium
Solution
verified
Verified by Toppr
Given that, the population of a town increases by 10.5% every year.
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
increases by 10.5% every year.
Also, the present population is 7,95,600.
To find out: Population of the town a year ago.
Let the population of the town a year ago be x.
∴ Population 1 years ago=
100+increase%
100
×present population
⇒x=
110.5
100
×795600=720000
Hence, the population of the town a year ago was 7,20,000.
mark me as brainlist
Class 11
>>Applied Mathematics
>>Basics of financial mathematics
>>Accumulation with simple and compound interest
>>The population of a town increases by 10
Question
Bookmark
The population of a town increases by 10.5% every year. If its present population is 7,95,600, what was it a year ago.
Medium
Solution
verified
Verified by Toppr
Given that, the population of a town increases by 10.5% every year.
Also, the present population is 7,95,600.
To find out: Population of the town a year ago.
Let the population of the town a year ago be x.
∴ Population 1 years ago=
100+increase%
100
×present population
⇒x=
110.5
100
×795600=720000
Hence, the population of the town a year ago was 7,20,000.