Answer:

Given that, the population of a town increases by 10.5% every year.

Also, the present population is 7,95,600.

To find out: Population of the town a year ago.

Let the population of the town a year ago be x.

∴ Population 1 years ago=

100+increase%

100

×present population

⇒x=

110.5

100

×795600=720000

Hence, the population of the town a year ago was 7,20,000.

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Answer:

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>>The population of a town increases by 10

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The population of a town increases by 10.5% every year. If its present population is 7,95,600, what was it a year ago.

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Solution

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Given that, the population of a town increases by 10.5% every year.

Also, the present population is 7,95,600.

To find out: Population of the town a year ago.

Let the population of the town a year ago be x.

∴ Population 1 years ago=

100+increase%

100

×present population

⇒x=

110.5

100

×795600=720000

Hence, the population of the town a year ago was 7,20,000.