Answer:

The take-off speed is 6.26 m/s

Explanation:

1. The Philippine tarsier is capable of jumping to a height of 2.0 m in hunting for food. Determine the take-off speed of the tarsier.

We have the following data:

Vf (final velocity) = 0 m/s (at maximum height)

Vi (initial velocity) = unknown

g (acceleration of gravity) ≈ -9.8 m / s²

h (height) = 2.0 m

Solution:

To solve this problem, we can use the formula Vf² = Vi²  + 2ad, to solve for Vi,  we can use the formula Vi = √Vf² - 2ad

Vi = √Vf² - 2ad

    = √0 - (2× -9.8 m / s² × 2.0 m)

    = √0 - (-39.2 m²/s²)

    = √39.2 m²/s²

    = 6.26 m/s

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