Your answer is 9 Now let me explain, Let the two equal sides be x. And the hypotenuse be y. Therefore the hypotenuse(y) = x✓2[Right angled triangle] ATQ, => 2x+y = 6(✓2+1) => 2x+x✓2 = 6(✓2+1) [ plotting y = x✓2 ] => x✓2(✓2+1) = 6(✓2+1) => x✓2 = 6 => x = 6/✓2 => x = 3✓2 So its area would be ½x² = ½(3✓2)² = ½18 = 9.
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Your answer is 9Now let me explain,
Let the two equal sides be x.
And the hypotenuse be y.
Therefore the hypotenuse(y) = x✓2[Right angled triangle]
ATQ,
=> 2x+y = 6(✓2+1)
=> 2x+x✓2 = 6(✓2+1) [ plotting y = x✓2 ]
=> x✓2(✓2+1) = 6(✓2+1)
=> x✓2 = 6
=> x = 6/✓2
=> x = 3✓2
So its area would be ½x²
= ½(3✓2)²
= ½18
= 9.
Hope it helped.
If yes show your gratitude.
Have a nice day.