a+b+5=12
a+b=7⇒a=7−b...(1)
a2+b2=52
a2+b2=25...(2)
From (1) and (2)
(7−b)2+b2=25
49+b2−14b+b2=25
2b2−14b+24=0
b2−7b+12=0
(b−4)(b−3)=0
⇒b=4,3
a=7−b⇒a=3,4
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[tex]\underline{\underline{\pink{\huge\sf Solution}}}[/tex]
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Answers & Comments
a+b+5=12
a+b=7⇒a=7−b...(1)
a2+b2=52
a2+b2=25...(2)
From (1) and (2)
(7−b)2+b2=25
49+b2−14b+b2=25
2b2−14b+24=0
b2−7b+12=0
(b−4)(b−3)=0
⇒b=4,3
a=7−b⇒a=3,4
yah Lo Tumhare Kasam ka answer de diya Thanks aur follow karo fatafat
Verified answer
[tex]\underline{\underline{\pink{\huge\sf Solution}}}[/tex]
"Kindly Refer to the above attachment for the solution" !!
Hope it helped!!
Thanks! ~