Then, its length =(2x+2) metres
Let the breadth be x m. The length will be (2x + 2) m.
Perimeter of swimming pool = 2(l + b) = 154 m
2(2x + 2 + x) = 154
2(3x + 2) = 154
Dividing both sides by 2, we obtain
293X + 2/2 = 154/2
3x + 2 = 77
On transposing 2 to R.H.S, we obtain
3x = 77 − 2
3x = 75
On dividing both sides by 3, we obtain
x = 25
2x +2 = 2 x 25+2 = 52
Hence, the breadth and length of the pool are 25 m and 52 m respectively.
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Verified answer
Then, its length =(2x+2) metres
[tex] = 2(Length + Breadth ) \\ \\ = 2(2x + 2x + x) \\ \\ = 6x + 4[/tex]
[tex]6x + 4 = 154 \\ \\ 6x = 154 - 4 \\ \\ 6x = 150 \\ \\ x = \frac{150}{6} \\ \\ x = 25[/tex]
[tex]Breadth = 25 \: m \\ \\ Length = (25 \times 2 + 2) \\ \\ = 52 \: m[/tex]
Let the breadth be x m. The length will be (2x + 2) m.
Perimeter of swimming pool = 2(l + b) = 154 m
2(2x + 2 + x) = 154
2(3x + 2) = 154
Dividing both sides by 2, we obtain
293X + 2/2 = 154/2
3x + 2 = 77
On transposing 2 to R.H.S, we obtain
3x = 77 − 2
3x = 75
On dividing both sides by 3, we obtain
x = 25
2x +2 = 2 x 25+2 = 52
Hence, the breadth and length of the pool are 25 m and 52 m respectively.