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• Given thta
• Given thtaPerimeter of a parallelogram =140 cm
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cm
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cm
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know that
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=70
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−15
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x=
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 2
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255 x=27.5 cm
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255 x=27.5 cm One side =27.5 cm
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255 x=27.5 cm One side =27.5 cmlong side =27.5+15
• Given thtaPerimeter of a parallelogram =140 cmLet the outside of parallelogram =x cmthen,long side =(x+15) cmNow, we know thatperimeter of parallelogram 140 cm2x+(x+15)=140x+x+15=702x=70−152x=55x= 255 x=27.5 cm One side =27.5 cmlong side =27.5+15long side =42.5 cm