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Answer:

Let's find the electron configurations of the metal ions:

1. Cr (Chromium): [Ar] 3d^5 4s^1

2. Mn (Manganese): [Ar] 3d^5 4s^2

3. Fe (Iron): [Ar] 3d^6 4s^2

4. Co (Cobalt): [Ar] 3d^7 4s^2

Now, let's look at the given pairs:

(1) [Cr(H2O)6]2+ and [Fe(H2O)6]2+

Both have d^6 configurations, so they have the same magnetic moment.

(2) [Mn(H2O)6]2+ and [Cr(H2O)6]2+

Both have d^5 configurations, so they have the same magnetic moment.

(3) [CoCl4]2– and [Fe(H2O)6]2+

[CoCl4]2– has a d^7 configuration, and [Fe(H2O)6]2+ has a d^6 configuration. They do not have the same magnetic moment.

(4) [Cr(H2O)6]2+ and [CoCl4]2–

[Cr(H2O)6]2+ has a d^6 configuration, and [CoCl4]2– has a d^7 configuration. They do not have the same magnetic moment.

Therefore, the pairs with the same magnetic moment are:

(1) [Cr(H2O)6]2+ and [Fe(H2O)6]2+

(2) [Mn(H2O)6]2+ and [Cr(H2O)6]2+

Explanation:

Answer:

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Class 12

>>Chemistry

>>Coordination Compounds

>>Crystal Field Theory

>>The pair having the same magnetic moment

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The pair having the same magnetic moment is :

[ At. No.: Cr = 24, Mn = 25, Fe = 26, Co = 27]

Correct option is A)

The pair having the same magnetic moment is

[Cr(H

2

O)

6

]

2+

and [Fe(H

2

O)

6

]

2+

In [Cr(H

2

O)

6

]

2+

, the chromium metal is in +2 oxidation state with 3d

4

outer electronic configuration and 4 unpaired electrons.

In [Fe(H

2

O)

6

]

2+

, the iron metal is in +2

oxidation state with 3d

6

outer electronic configuration and 4 unpaired electrons.

Since both complexes have same number of unpaired electrons, they have the same magnetic moment.

Solve any question of Coordination Compounds