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Number of ways of selection of 8 letters from 24 letters of which 8 are a, 8 are b and the rest unlike, is given byA. 8.28B. 27C. 10.27D. 8.27
Question
Number of ways of selection of 8 letters from 24 letters of which 8 are a, 8 are b and the rest unlike, is given by
A
B
C
loader
D
Solution
The correct option is C
The number of selections = coefficient of
x
8
in
(
1
+
2
.
)
= coefficient of
−
9
3
0
×
4
=
9.
8.
7.
1.
7
Putting x = 1, we get
8.2
10.2
Answer 10.2power7
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Answer:
Find solutions
CameraIcon
SearchIcon
MyQuestionIcon
Home
>
Number of ways of selection of 8 letters from 24 letters of which 8 are a, 8 are b and the rest unlike, is given byA. 8.28B. 27C. 10.27D. 8.27
Question
Number of ways of selection of 8 letters from 24 letters of which 8 are a, 8 are b and the rest unlike, is given by
A
B
C
loader
D
Solution
The correct option is C
The number of selections = coefficient of
x
8
in
(
1
+
x
+
x
2
+
.
.
.
.
.
.
.
.
.
.
+
x
8
)
(
1
+
x
+
x
2
+
.
.
.
.
.
.
.
.
.
+
x
8
)
.
(
1
+
x
)
8
= coefficient of
x
8
in
(
1
−
x
9
)
2
(
1
−
x
)
2
(
1
+
x
)
8
= coefficient of
x
8
in
(
1
+
x
)
3
(
1
−
x
)
−
2
= coefficient of
x
8
in
(
8
C
0
+
8
C
1
x
+
8
C
2
x
2
+
.
.
.
.
.
.
.
.
.
.
+
8
C
8
x
8
)
×
(
1
+
2
x
+
3
x
2
+
4
x
3
+
.
.
.
.
.
.
.
.
.
+
9
x
8
+
.
.
.
.
.
.
.
.
.
)
=
9.
8
C
0
+
8.
8
C
1
+
7.
8
C
2
+
.
.
.
.
.
.
.
.
.
.
.
.
.
+
1.
8
C
8
=
C
0
+
2
C
1
x
+
3
C
2
x
2
+
.
.
.
.
.
.
9
C
8
x
8
=
(
1
+
x
)
8
+
8
x
(
1
+
x
)
7
Putting x = 1, we get
C
0
+
2
C
1
+
3
C
2
+
.
.
.
.
.
.
.
.
+
9
C
8
=
2
8
+
8.2
7
=
2
7
.
(
1
+
8
)
=
10.2
7
.
Verified answer
The number of selections = coefficient of
x
8
in
(
1
+
x
+
x
2
+
.
.
.
.
.
.
.
.
.
.
+
x
8
)
(
1
+
x
+
x
2
+
.
.
.
.
.
.
.
.
.
+
x
8
)
.
(
1
+
x
)
8
= coefficient of
x
8
in
(
1
−
x
9
)
2
(
1
−
x
)
2
(
1
+
x
)
8
= coefficient of
x
8
in
(
1
+
x
)
3
(
1
−
x
)
−
2
= coefficient of
x
8
in
(
8
C
0
+
8
C
1
x
+
8
C
2
x
2
+
.
.
.
.
.
.
.
.
.
.
+
8
C
8
x
8
)
×
(
1
+
2
x
+
3
x
2
+
4
x
3
+
.
.
.
.
.
.
.
.
.
+
9
x
8
+
.
.
.
.
.
.
.
.
.
)
=
9.
8
C
0
+
8.
8
C
1
+
7.
8
C
2
+
.
.
.
.
.
.
.
.
.
.
.
.
.
+
1.
8
C
8
=
C
0
+
2
C
1
x
+
3
C
2
x
2
+
.
.
.
.
.
.
9
C
8
x
8
=
(
1
+
x
)
8
+
8
x
(
1
+
x
)
7
Putting x = 1, we get
C
0
+
2
C
1
+
3
C
2
+
.
.
.
.
.
.
.
.
+
9
C
8
=
2
8
+
8.2
7
=
2
7
.
(
1
+
8
)
=
10.2
7
Answer 10.2power7