Explanation:

Find the number of solutions of the equation, x

log x

(x+3) 2 =16

x log x

(x+3) 2=16

x loge

xloge

(x+3) 2 =16

Taking logarithm on both sides, loge

xloge

(x+3) 2loge

x=loge

16⇒(x+3) 2

=16⇒x=1,−7

But x=1, is not possible as the base of logarithm cannot be 1.

−7 is not possible as the log of a negative quantity does not exist.

So, the number of solution =0.

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