The number of shoes sold per day at retail store is shown in the below.
X: 19 20 21 22 23
P(X): 0.4 0.2 0.2 0.1 0.1
Formula to be used:
a. Mean:
b. Variance:
c. Standard Deviation:
Solution:
Multiply value of the random variable x by the corresponding probability:
X • P(X)
Get the mean by getting the sum of X • P(X)
μ = ΣX • P(X)
μ = 7.6 + 4 + 4.2 + 2.2 + 2.3
Subtract the mean from each value of the random variable x:
X - μ
Square the results of X - μ
(X - μ)²
Multiply the results of (X - μ)² by the corresponding probability:
(X - μ)² • P(X)
Get the sum of the results in (X - μ)² • P(X) to get the variance:
Get the square root of the variance to get the standard deviation:
The number of patients seen in the Emergency Poor in any given hour is a
random variable represented by x. The probability distribution for x is:
X: 10 11 12 13 14
μ = 4 + 2.2 + 2.4 + 1.3 + 1.4
tex]14 • 7.29 = 102.06[/tex]
X: 0 1 2 3 4
P(X): 1/16 1/4 3/8 1/4 1/16
μ = 0 + 0.25 + 0.75 + 0.75 + 0.25
tex]4 • 4 = 16[/tex]
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Answers & Comments
Statistics and Probability
Independent Activity 1:
The number of shoes sold per day at retail store is shown in the below.
X: 19 20 21 22 23
P(X): 0.4 0.2 0.2 0.1 0.1
Independent Assessment 1:
Formula to be used:
a. Mean:
b. Variance:
c. Standard Deviation:
Solution:
Multiply value of the random variable x by the corresponding probability:
X • P(X)
Get the mean by getting the sum of X • P(X)
μ = ΣX • P(X)
μ = 7.6 + 4 + 4.2 + 2.2 + 2.3
Subtract the mean from each value of the random variable x:
X - μ
Square the results of X - μ
(X - μ)²
Multiply the results of (X - μ)² by the corresponding probability:
(X - μ)² • P(X)
Get the sum of the results in (X - μ)² • P(X) to get the variance:
Get the square root of the variance to get the standard deviation:
Independent Activity 2
The number of patients seen in the Emergency Poor in any given hour is a
random variable represented by x. The probability distribution for x is:
X: 10 11 12 13 14
P(X): 0.4 0.2 0.2 0.1 0.1
Independent Assessment 2:
Formula to be used:
a. Mean:
b. Variance:
c. Standard Deviation:
Solution:
Multiply value of the random variable x by the corresponding probability:
X • P(X)
Get the mean by getting the sum of X • P(X)
μ = ΣX • P(X)
μ = 4 + 2.2 + 2.4 + 1.3 + 1.4
Subtract the mean from each value of the random variable x:
X - μ
Square the results of X - μ
(X - μ)²
Multiply the results of (X - μ)² by the corresponding probability:
(X - μ)² • P(X)
tex]14 • 7.29 = 102.06[/tex]
Get the sum of the results in (X - μ)² • P(X) to get the variance:
Get the square root of the variance to get the standard deviation:
Independent Activity 3:
X: 0 1 2 3 4
P(X): 1/16 1/4 3/8 1/4 1/16
Independent Assessment 3:
Formula to be used:
a. Mean:
b. Variance:
c. Standard Deviation:
Solution:
Multiply value of the random variable x by the corresponding probability:
X • P(X)
Get the mean by getting the sum of X • P(X)
μ = ΣX • P(X)
μ = 0 + 0.25 + 0.75 + 0.75 + 0.25
Subtract the mean from each value of the random variable x:
X - μ
Square the results of X - μ
(X - μ)²
Multiply the results of (X - μ)² by the corresponding probability:
(X - μ)² • P(X)
tex]4 • 4 = 16[/tex]
Get the sum of the results in (X - μ)² • P(X) to get the variance:
Get the square root of the variance to get the standard deviation:
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10 • 1.69= 16.910•1.69=16.9
11 • 0.09 = 0.9911•0.09=0.99
12 • 0.49 = 5.8812•0.49=5.88
13 • 2.89 = 37.5713•2.89=37.57